The height of a street light is 54 feet. it casts a 32−foot shadow. at the same time, a man standing next to the street light casts a 4−foot shadow. how tall is the man? if needed, round the answer to the nearest hundredth.

  6.75 ft

Step-by-step explanation:

The man's shadow is 1/8 the length of the pole's shadow, so we presume the man is 1/8 the height of the pole:

  (54 ft)/8 = 6.75 ft . . . . height of the man

We have to assume that the source of light casting the shadows is not the street light.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

answer: 7

step-by-step explanation: