Be sure to answer each question the right way or no points : )

1)   (1, -2) >Last option

2)  (-3/4 , -1/5) > First option

Step-by-step explanation:

1)

8x + 2y = 4      (1)

-4x + 3y = -10  (2)

Multiply equation(2)  by 2

2(-4x + 3y)  = 2(-10)

-8x + 6y = -20

So now you have

8x + 2y = 4

-8x + 6y = -20

add

8y = -16

 y = -2

Substitute y = -2 into 8x + 2y = 4

8x + 2(-2) = 4

8x - 4 = 4

8x = 8

 x = 1

Solution (1 , -2)

2)

8g - 5h = 7 (1)

4g + 10h = 1 (2)

Multiply equation(2)  by -2

-2(4g + 10h)  = -2(1)

-8g - 20h = -2

Now you have 2 equations

8g - 5h = 7

-8g - 20h = -2

add

-25h = 5

    h = -1/5

Substitute h = -1/5 into 8g - 5h = 7

8g - 5(-1/5) = 7

8g + 1 = 7

8g = -6

 g = -3/4

Solution (-3/4 , -1/5)

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.