Aregular octagon has side length 10.9 in. the perimeter of the octagon is 87.2 in and the area is 573.67 in2. a second octagon has side lengths equal to 21.8 in. find the area of the second octagon. round to the nearest hundredth. 261.60 in2 2294.68 in2 317.06 in2 142.66 in2

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94

do have an equation or graph or

step-by-step explanation: