A500 g model train car traveling at 0.8 m/s collides with a 300 g stationary car. the cars hook up and move off down the track together. how fast are they going? ( also how do i do it )

0.5 m/s

Step-by-step explanation:

A 500 g model train car traveling at 0.8 m/s collides with a 300 g stationary car.

Initial velocity of train,

Initial velocity of car,

Mass of train,

Mass of car,

The cars hook up and move off down the track together.

Let the final velocity of car and train,

Using conservation of momentum,

Momentum before collision = Momentum after collision

Hence, After collision they will going with 0.5 m/s

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.