How do you solve algebra special systemssolve each system of linear equations. y equals negative x minus 3 x plus y equals 4

Y=-X-3
X+Y=4
You'll want to get X or Y by itself, which in this question it already is.

After that, use substitution (Plug -X-3 in place of Y in X+Y=4)

Equation should look like X+(-X-3)=4

Solve that equation

X+(-X-3)=4

X+(-X) cancels eachother out, leaving you with (-3)=4

Add 3 to both sides of (-3)=4, leaving you with 0=7

0 Can't equal 7, so this equation has no solutions