Acampus survey of owls indicates that 7% are charming, 4% are modest, and 3% are both charming and modest. find the probability that an owl is modest, given that he/she is charming. given that a student isn't modest, what is the probability that they are not charming?

P(modest | charming) = 0.4286

P(not charming | not modest) = 0.896

Step-by-step explanation:

This is a conditional probability problem.

Let A and B be two dependent events, then:

The probability of A given B is written as:

P (A | B) =

So:

The probability that an OWL is modest given that he/she is charming is:

P (modest | charming) =

P (modest | charming) =

P (modest | charming) = 0.4286

Then, the probability that a student is not modest is:

The probability that a student is not charming and not modest is:

So:

P(not charming | not modest) =

P(not charming | not modest) =

P(not charming | not modest) = 0.9583

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300