Arotating sprinkler waters a circular region of a lawn with a diameter of 50 feet. what is the area of the lawn being watered? use 3.14 for pi. enter your exact value - do not

A =1962.5 ft^2

Step-by-step explanation:

We want to find the area of the circle

A = pi * r^2

We know the diameter

d = 2r

50 = 2r

Divide by 2

50/2 = 2r/2

25 =r

A = pi * (25)^2

A = pi*625

Let pi = 3.14

A = (3.14) * 625

A =1962.5 ft^2

i pretty sure it is

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3