Find the different quotient f(x+h)-f(x)/h given the function of f(x)= 3x^2+2

This is 6x.

Step-by-step explanation:

f(x) =  3x^2 + 2

The differential coefficient (f'(x)) is the limit as h-->0 of [ f(x+h)-f(x)]/ h.

f'(x) = [3(x + h)^2 + 2  - (3x^2 + 2)] / h

= ( 3x^2  + 6hx + 3h^2 + 2 - 3x^2 - 2) / h

= (6hx + 3h^2) / h

= 6x + 3h

As h approaches very close to 0 we can neglect the 3h.

so f'(x) = 6x (answer).

i got 10.28 but that rounds up to 10.3

the answer is su.k.my? ? co.kc