What is the name of the shape graphed by the function r = 1 -2 sin theta

Limacon of Pascal

Step-by-step explanation:

The given polar functin is

r =1-2sint

We find that when r =0

2sint =1

sint =1/2

Or t = 60, 120

SO it passes through origin for 60, 120 degrees

There is a loop formed between 30 and 150 and again it completes a big round around the loop

When R=1, we find t =0, pi, 2pi

When R=2, we get sint =-1/2

Hence angles are 210 and 330 degrees

Since sin t lies between -1 and 1 only we have

When sint =-1, r has maximum 3

and when sint =1, r cannot have -1 but 0

So r can take values between 0 and 3

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.

ummm seems that u didnt post the attachement !