Ascientist launched an object upward at a speed of 32 ft per second from a height of 240 feet. the height of the object is modeled by the equation h = 240 + 32t – 16t2. after how much time will the object hit the ground? a 3 seconds b 5 seconds c 12 seconds d 20 seconds

B5 seconds

Step-by-step explanation:

h = 240 + 32t – 16t^2

When is this equation 0

0 = 240 + 32t – 16t^2

Factor out 16

0 = -16(-15-2t+t^2)

   = -16(t^2-2t-15)

What 2 numbers multiply to -15 and add to -2

-5*3 = -15

-5+3 =-2

0 = -16(t-5) (t+3)

Using the zero product property

t-5=0   t+3=0

t=5    t=-3

Since time cannot be negative

t=5 seconds

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.