The length of a rectangle is 3 times longer than its width. if the area of the rectangle is 24 square inches, then what is the perimeter of the rectangle?

  =16sqrt(2) inches

Step-by-step explanation:

Let w = width

The length is 3 times longer than the width

L =3w

A = l*w

24 = (3w) *w

24 = 3w^2

Divide each side by 3

24/3 = 3w^2/3

8 = w^2

Take the square root of each side

sqrt(8) = sqrt(w^2)

sqrt(4)sqrt(2) = w

2sqrt(2) =w

Now we can find the length

L = 3w

L = 3(2sqrt(2))

L =6sqrt(2)

The final step is to find the perimeter

Perimeter is 2(l+w)

P =2(l+w)

   =2(2sqrt(2) +6sqrt(2))

Combine like terms

   =2(8sqrt(2))

  =16sqrt(2)

c. (0.6,-1.4)

step-by-step explanation:

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