The distance between new york city, ny, and louisville, ky is 720 miles. one morning a train traveling 80 mph left from new york. two hours later a slower train, traveling at 60 mph, left louisville. how many hours will the slower train travel for before both trains will arrive at the same point?

2 hours

Step-by-step explanation:

Given : The distance between New York City, NY, and Louisville, KY is 720 miles. One morning a train traveling 80 mph left from New York. Two hours later a slower train, traveling at 60 mph, left Louisville.

To find : How many hours will the slower train travel for before both trains will arrive at the same point?

Solution : Let the distance covered by NY is x

and  let the distance covered by KY is y

Total distance covered is     ........[1]

→ New York city,

Distance traveled = x

Speed of the train = 80 mph

Time taken = t+2

Formula is

.......[2]

→ Louisville,

Distance traveled = y

Speed of the train = 60 mph

Time taken = t

Formula is

.......[3]

Put the value of t from [3] into [2]

 ......[4]

Now, we solve equation [1] and [4],

Put the value of y from [1] and put back in [4],

Put x=480 in [1]

So, The distance covered by train from New York city is x=480 miles

The distance covered by train from Louisville is y=240 miles.

Now put value of y in [3] to get time,

So, The time taken by train from Louisville is 4 hr.

The time taken by train from New York city is t+2=4+2=6 hr.

→ 6-4=2 hours will the slower train travel for before both trains will arrive at the same point.

i will pick c put check it over to be sure

step-by-step explanation:

47 - 90 = 43

43 - 180 = x

x = 137