What is the equation for the line that passes through (0,-9) and has a slope equal to 5?

y=5x-9

Step-by-step explanation:

Equation of line in slope-intercept form is:

y=mx+c where m denotes slope of line and c denotes y-intercept.

y-intercept is a point on the line where value of x is zero.

Slope is defined as steepness of a line and also called gradient.It is denoted by m.

From question statement ,we observe that

slope=m= 5

y-intercept at (0,-9) which means c=-9.

Putting the value of slope and y-intercept in slope-intercept form,we get

y=(5)x+(-9)

y=5x-9 is equation of line that passes through (0,-9) and has a slope equal to 5.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.