If f(x)=x-6/x and g(x)=x+4 and h(x)=3x-2 what is h(f(g(

The answer is h(f(g(x))) =

Step-by-step explanation:

Given f(x)= x-6/x

g(x) = x+4

h(x) =3x-2

We have to find h(f(g(x))) ?

Basically it is a composite function i.e.

function within a function

So now f(g(x))=f(x+4)

i.e. we are going to put x+4 in place of g(x)

f(g(x))= x+4 -

Multiplying both sides by x+4

f(g(x)) *x+4=(x+4) -6

Now dividing both sides by x+4

f(g(x)) =/(x+4)

Now h(f(g(x)))= h()

=3( -2

Multiplying both sides by x+4

h(f(g(x)) *(x+4) =3* -6 -2*(x+4)

Now dividing both sides by (x+4)

h(f(g(x)) =3* -2

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.

the first one

step-by-step explanation:

just id the test.