Mathematics, 22.06.2019 17:30 nadia74

Which system of inequalities represents region z?

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Answer from: smithsa10630

The system of inequalities is

$y\geq 3x-2$

Step-by-step explanation:

step 1

Find the equation of the solid blue line

Let

A(0,-2), B(1,1)

Find the slope of AB

m=(1+2)/(1-0)=3

The equation of the line into slope intercept form is equal to

y=mx+b

we have

m=3

b=-2 ----> the point A is the y-intercept

substitute

y=3x-2 -----> equation of the solid blue line

The solution of the inequality is the shaded area above the solid line

therefore

The first inequality is

$y\geq 3x-2$

step 2

Find the equation of the dashed red line

Let

C(0,2), D(5,1)

Find the slope of CD

m=(1-2)/(5-0)=-1/5

The equation of the line into slope intercept form is equal to

y=mx+b

we have

m=-1/5

b=2 ----> the point C is the y-intercept

substitute

y=-(1/5)x+2 -----> equation of the dashed red line

The solution of the inequality is the shaded area below the dashed line

therefore

The second inequality is

The system of inequalities is

$y\geq 3x-2$

Answer from: Quest

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Answer from: Quest

$y> \frac{1}{3}x$ and y≤ -x +4 .

step-by-step explanation:

we are given a graph for system of inequalities.

in order to write the system of inequalities for the given graph, we need to find the inequality for each of the line separately.

let us find the slope of dotted line first.

taking two coordinates on the graph.

let us say (0,0) and (3,1).

let us find the slope of the line now.

slope of the dotted line would be = $\frac{1-0}{3-0} = \frac{1}{3}$ .

y-intercept of dotted line is y=0 only.

plugging slope m= $\frac{1}{3}$ and b=0 in slope-intercept form y=mx+b, we get

$y=\frac{1}{3}x$ .

the line is shaded up of that dotted line.

therefore, for shading up we would take greater than inequality symbol > .

and because it's a dotted line we would take only > symbol in place of = sign in above equation of line.

therefore, inequality for dotted line would be

$y> \frac{1}{3}x$ .

let us take two points (3,1) and (0,4) on the solid line.

slope of the solid line would be = $\frac{4-1}{0-3} = \frac{3}{-3}=-1$ .

for the solid line we have y-intercept b= 4.

plugging slope m= -1 and b=4 in slope-intercept form y=mx+b, we get

y = -1x + 4.

the line is shaded down of that solid line.

therefore, for shading down we would take less than inequality symbol < .

and because it's a solid line we would take ≤ symbol in place of = sign in above equation of line.

therefore, inequality for solid line would be

y≤ -x +4 .
Write a system of inequalities to represent the shaded portion of the graph.

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