Explain how you could write a quadratic function in factored form that would have a vertex with an x-coordinate of 3 and two distinct roots.

On edge, this would be the explanation. Just use these examples but change it up!

The answer is f(x) = (x-3)²-h = (x-3-√h)(x-3+√h).

Step-by-step explanation:  We are given to write a quadratic function in factored form that would have a vertex with an x-coordinate of 3 and two distinct roots.

A quadratic function with vertex having x-coordinate k takes the form of a parabola as follows:

Here, 'k' and 'h' are both real.

Since we the the x-coordinate of the vertex as 3, so k = 3.

Therefore, the quadratic function becomes

This is the required factored form of the quadratic function.

See the attached graph, where the x-coordinate of the vertex is 3 and h is taken to be 2 units.

21

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180