Use the graph that shows the solution to f(x)=g(x) . f(x)=1/x−2 g(x)=x−2 what is the solution to f(x)=g(x) ? select each correct answer. −1 1 2 3 use the graph that shows the solution to f(x)=g(x) . f(x)=x^2+4x+2 g(x)=(1/2)^ x+1 what is the solution to f(x)=g(x) ? x=−1 x = 0 x = 2 x = 3

The solution to f(x) = g(x) is 1 and 3

The functions are given as:

To determine the solution to f(x) = g(x), we start by plotting the graphs of f(x) and g(x).

See attachment for the graph

From the attached graph, we have the following points of intersection at:

x = 1 and x = 3

Hence, the solution to f(x) = g(x) is 1 and 3

Read more about graph solutions at:

link

1.  x=3   x=1

2.  x=0

Step-by-step explanation:

We want f(x) to equal g(x)

f(x)=g(x)

1/(x-2) = (x-2)

Using cross products

1 = (x-2) * (x-2)

1 = x^2 -2x-2x+4

Subtract 1 from each side

1-1 = ^2 -2x-2x+4-1

0 = x^2 -4x+3

Factoring

What number multiplies to 3 and adds to -4

-3*-1 = 3

-3+-1 = -4

0= (x-3) (x-1)

Using the zero product property

x-3 =0     x-1=0

x=3   x=1

2.  f(x)=x^2+4x+2

g(x)=(1/2)^ x+1

From the graph,we can see they intersect at x=0

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )