All my points to whoever can solve this 5z2−9z=−7z−5 solve the following quadratic equation by using the quadratic formula. if needed, submit your answer as a fraction reduced to lowest terms or round your answer to two decimal places. there are 2 different answers

1/5 + 2/5 i sqrt(6) = .2 + .98i

1/5 - 2/5 i sqrt(6) = .2 - .98i

Step-by-step explanation:

5z^2−9z=−7z−5

We need to get all the terms on one side (set the right side equal to zero)

Add 7z to each side

5z^2−9z+7z=−7z+7z−5

5z^2−2z=−5

Add 5 to each side

5z^2−2z+5=−5 +5

5z^2−2z+5=0

This is in the form

az^2 +bz+c = 0 so we can use the quadratic formula

where a = 5   b = -2  and c = 5

-b± sqrt(b^2-4ac)

  2a

-(-2)± sqrt((-2)^2-4(5)5)

  2(5)

2± sqrt(4-100)

10

2± sqrt(-96)

10

2± sqrt(16)sqrt(-1) sqrt(6)

10

2± 4i sqrt(6)

10

1/5 ± 2/5 i sqrt(6)

Splitting the ±

1/5 + 2/5 i sqrt(6) = .2 + .98i

1/5 - 2/5 i sqrt(6) = .2 - .98i

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it