Aball is thrown directly up in the air from a height of 5 feet with an initial velocity of 60 ft/s. ignoring air resistance, how long until the ball hits the ground? use the formula where h is the height of the ball in feet and t is the time in seconds since it is thrown. round your answer to the nearest tenth.
When the ball hits the ground then height is 0
So we replace h with 0 and solve for t
a= -16 , b= 60 and c= 5
Apply quadratic formula to solve for t
Now make two fractions and solve for x
So answer is 3.8 seconds
Time, t = 3.8 seconds
It is given that,
A ball thrown up in air from a height of 5 feet.
Initial velocity, v₀ = 60 ft/s
When an object is thrown with initial velocity of v then the equation of motion is given by :
s₀ = height at t = 0, s₀ = 5 ft
Solving above quadratic equation, we get :
t = 3.8 seconds.
Hence, the correct option is (B) " 3.8 seconds ".