What is the factored form of the expression? d^2 - 14d + 49

d^2 - 14d + 49 = (d-7)(d-7).

Step-by-step explanation:

Given the expression is d^2 - 14d + 49.

d^2 - 14d + 49 = d^2 - 2*7*d + 7^2

We know the formula of square of difference as given below:-

x^2 - 2*x*y + y^2 = (x-y)^2

Using the above formula in the problem, here x = d and y = 7.

d^2 - 2*7*d + 7^2 = (d-7)^2

d^2 - 2*7*d + 7^2 = (d-7)(d-7)

So, d^2 - 14d + 49 = (d-7)(d-7).

(d-7)(d-7)

Step-by-step explanation:

We have to make factored form of the expression.

Given expression is :

d²-14d+49

Split the middle term to make the equation into two groups such that the sum of 2 numbers should be -14 and their product be 49.

d²-7d-7d+49

Making two groups and taking the common term out:

d(d-7)-7(d-7)

Take (d-7) common

(d-7)(d-7) which is factored form of d²-14d+49.

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

your answer is  

a.

5

step-by-step explanation: