Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

The function that are undefined for (x=0) is   and and this can be determined by putting (x=0) in all the given expressions.

Given :

Function 1 -

Function 2 -

Function 3 -

Function 4 -

Evaluate each function at (x = 0) to determine which function is undefined for (x = 0).

Function 1 -

put (x = 0) in above function:

Therefore, it can be concluded that the above function is not defined for (x=0).

Function 2 -

put (x = 0) in above function:

Therefore, it can be concluded that the above function is not defined for (x=0).

Function 3 -

put (x = 0) in above function:

Therefore, it can be concluded that the above function is defined for (x=0).

Function 4 -

put (x = 0) in above function:

Therefore, it can be concluded that the above function is defined for (x=0).

For more information, refer to the link given below:

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For this case, we must indicate which of the given functions is not defined for

By definition, we know that:

has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

is not defined, the term inside the root is negative when .

While if it is defined for

, your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

with x = 0: is defined.

with x = 0: in the same way is defined.

Option b

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.