If f(x)=x+7 and g(x)=1/x-13, what is the domain of (f•g)(x)

F(x) = x+7

g(x) = 1/(x-13)

fog(x) = [1/(x-13)] + 7

The denominator of the fraction cannot be equal to zero.

So, the domain of fog(x) is x∈R~{13}

Step-by-step explanation:

step-by-step explanation:

first you will have to convert 3/4 into a decimal

which is .75

then you will have to divide 1.5 by .75

which is 2

no you have to divide