Find an equation for the line that is perpendicular to the graph of 5x-3y=9 if the two lines intersect at x=30

in Point Slope Form

Step-by-step explanation:

The line 5x - 3y = 9 converts to slope intercept form as y = 5/3 x-3. When x = 30, it has the value y = 5/3(30) - 3 = 50 - 3 = 47. SO it has the point (30,47).

This line has a slope of 5/3. The line perpendicular to it will have the negative reciprocal slope -3/5. Using this slope and the point (30,47), we write the ine in point slope form:

your answer is 228

step-by-step explanation:

add the top and bottom bases together, then divide them by 2, then multiply by the height.

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.