Given: △abc, bc> ac, d∈ ac , cd=cb prove: m∠abd is acute

Step-by-step explanation:

Given: △ABC, BC>AC, D∈ AC , CD=CB

To prove: m∠ABD is acute

Proof: In ΔABC, the angle opposite to side BC is ∠BAC and  the angle opposite to side  AC is ∠ABC.

Now, it is given that  BC>AC, then ∠BAC>∠ABC..                       (1)

In ΔBDC, using the exterior angle property,

∠ADB=∠DBC+∠BCD

∠ADB=∠DBC+∠BCA

⇒∠ADB>∠BAC                            (2)

From equation (1) and (2), we get

∠ADB>∠BAC

⇒∠ADB>∠ABC

⇒DB>AB

Hence,    m∠ABD is acute            

36 is the final answer! : )

answer: i think it is (1,-2)