7x^2-9x+5=0 find the discriminant and number of real solutions

Discriminant = -59

There are no real solutions

Step-by-step explanation:

7x^2-9x+5=0

We apply the discriminant formula

D =b^2 -4*a*c

Where a, b and c are obtained by expressing the quadratic equation in the form ax^2 +bx+c =0

D = (-9)^2 - 4*(7)*(5)  = -59

Since D <0 The solutions are complex conjugates

a - base

b - exponent

so,

answer: both chords and diameters have two endpoints on a circle. diameters must intersect the center of a circle.