Find the area of the region between a regular hexagon with sides of 6" and its inscribed circle.

  (54√3 - 27π) in²

Step-by-step explanation:

The radius of the inscribed circle is the apothem of the hexagon, so is ...

  (6 in)·sin(60°) = 3√3 in

The area of the hexagon is half the product of this and the perimeter of the hexagon (6 times the side length).

  A = (1/2)(6·6 in)(3√3 in) = 54√3 in²

The area of the circle is ...

  A = π·r² = π(3√3 in)² = 27π in²

Then the region between the hexagon and its inscribed circle will be ...

  hexagon area - circle area =

  (54√3 - 27π) in²

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation:

easy its decreasing

step-by-step explanation:

because its top point is at the to of the graph on the left side (atleast from the veiw i see it) now if that top point wast in the lower part of the graph it would be increasing hope this have a nice day