Which polynomial equation of least degree has -2, -2, 3, and 3 as four of its roots? (x + 2)(x - 3) = 0 (x - 2)-2(x + 3)3 = 0 (x-2 + 2)(x2- 3) = 0 (x + 2)2(x - 3)2 = 0

last option

(x+2)²(x-3)²=0

The correct option is D) (x+2)²(x-3)² = 0

Step-by-step explanation:

We need to find the polynomial equation of least degree has -2, -2, 3, and 3 as four of its roots

we will check each option by equating them to zero

Check part A)

(x + 2)(x - 3) = 0

if x + 2 =0 ⇒ x = -2

if x - 3 =0 ⇒ x = 3

Check part B)

(x - 2)-2(x - 3)³ = 0

if x - 2 =0 ⇒ x = 2

if x - 3 = 0 ⇒ x = 3, 3 ,3                          ( since, multiplicity of (x - 3)³ is 3 )

Check part C)

(x-2+2)(x²-3) = 0

if (x-2+2) = 0 ⇒ x = 0

if x²-3 = 0 ⇒ x² = 3  ⇒ x = √3

Check part D)

(x+2)²(x-3)² = 0

if (x+2)² = 0 ⇒ x = -2, -2                          ( since, multiplicity of (x + 2)² is 2 )

if (x-3)² = 0 ⇒ x² = 3, 3, 3                        ( since, multiplicity of (x - 3)² is 2 )

In this part polynomial equation of least degree has -2, -2, 3, and 3 as four of its roots

Hence, the correct option is D) (x+2)²(x-3)² = 0

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

0.32

step-by-step explanation:

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