Two poles, ab and ed, are fixed to the ground with the of ropes ac and ec, as shown: what is the approximate distance, in feet, between the two poles? 6.93 feet 8.66 feet 12.32 feet 15.59 feet

15.59 feet

Step-by-step explanation:

We need to find BC and CD

First find BC

We can use the Pythagorean theorem

AB^2 + BC^2 = AC^2

11^2 + BC^2 = 13^2

121 + BC^2 =169

Subtract 121 from each side

121-121+BC^2 = 169-121

BC^2 = 48

Take the square of each side

sqrt(BC^2 ) = sqrt( 48)

BC = 6.92820323

then we need to find CD

We can use the Pythagorean theorem

CD^2 + DE^2 = CE^2

CD^2 + 5^2 = 10^2

CD^2 + 25 =100

Subtract 25 from each side

CD^2 + 25-25 =100-25

CD^2 = 75

Take the square of each side

sqrt(CD^2 ) = sqrt( 75)

BC = 8.660254038

BD = BC +CD

     = 6.92820323 + 8.660254038

     15.58845727

with btw u said 100pts but it clearly says

i answerd and just got 10pts

no hate