In a right triangle δabc, the length of leg ac = 5 ft and the hypotenuse ab = 13 ft. find: b the length of the angle bisector of angle ∠a.

  b = (5/3)√13

Step-by-step explanation:

The cosine of ∠A is AC/AB = 5/13.

The cosine of half of ∠A is given by the half-angle formula ...

   cos(A/2) = √((1 +cos(A))/2) = √((1 + 5/13)/2) = √(9/13) = 3/√13

The length of the segment b is found from ...

  cos(A/2) = 5/b . . . . . adjacent side/hypotenuse

  b = 5/cos(A/2) = 5/(3/√13)

  b = (5/3)√13

answer: i believe it’s 245.04

step-by-step explanation: