Can someone check if i did this right since i really want to make sure it’s correct. if you do you so much

(a) scale factor = 11, x = 33

(b) scale factor = 1/8, x = 7

Step-by-step explanation:

The value you get for x in question (a) is correct. The scale factor is not quite right.

A scale factor answers the question of "What do I have to do to the first figure to get to the second one"?

So for (a) you start out with 10 in the first figure and get to 110 in the second one.

Scale factor = second figure / first figure = 110/10 = 11

So your scale factor should be 11.

The next thing you do is

Size of second figure = scale factor * size of first figure.

Size of second figure = 11 * 3 = 33 which you already had.

(b)

Scale factor = second figure / first figure = 6/48 = 1/8

X = scale factor * size of second figure.

x = 1/8 * 56 = 7

The problem does not change in method  if you have to go from the second figure to the first, but you have to be careful how you set it up.

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!