centre = (2, 6)
The centre is at the midpoint of the diameter.
Use the midpoint formula to find the centre
centre = [(- 2 + 6), (8 + 4)] = (2, 6)
answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.
u also answered this so i think u would know but i am here to
put in or use mine