Write an equation of a line in slope intercept form that is perpendicular to the line 2x -3y = 12 and passes through the point (2, 6).

The equation of the line would be y = -3/2x + 9

Step-by-step explanation:

In order to solve this, start by finding the slope of the original line. You can do this by solving for y.

2x - 3y = 12

-3y = -2x + 12

y = 2/3x - 4

Now that we have a slope of 2/3, we know that the perpendicular slope is -3/2 (since perpendicular lines have opposite and reciprocal slopes). We can use this and the new point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 6 = -3/2(x - 2)

y - 6 = -3/2x + 3

y = -3/2x + 9

99

step-by-step explanation:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!