At dinner, 2/5 of the people had fish and 1/3 had chicken. if everyone else had lamb, what fraction of the people had lamb? and if 40 people had lamb , calculate the total number of people at the dinner.

x = 150 people at dinner

Step-by-step explanation:

(2/5) x - had fish

(1/3) x - had chicken

The sum of this two fractions is:  2/5 + 1/3

First, we must bring these two fractions to the same denominator.

First fraction we will multiply with number 3 and get:

(2/5) · 3 = 6/15

Second fraction we will multiply with number 5 and get:

(1/3) · 5 = 5/15

Now we can calculate the sum of this two fraction:

6/15 + 5/15 = 11/15

The fraction of the people which had lamb is :

(4/15) x = 40 => x = 40 : (4/15) = 40 · 15/4 = 150

x = 150 people had dinner.

God with you!!!

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

gimme brainliest > : 3