Asystem of equation is shown below 6x - 2y equals 3 . and 5x + 3y equals 4. would you solve by substitution or elimination? and why

see below

Step-by-step explanation:

6x-2y =3

5x+3y =4

I would use elimination

To solve for one variable in either equation, you would end up with fractions, and fractions are hard to work with.

Take the firs equation.  to solve for y

6x -2y =3

-2y = -6x+3

y = -6x/-2 +3/-2

The last term is a fraction and then we substitute it into the other equation.

With elimination

Multiply the first equation by 3 and the second equation by 2

18x -6y =9

10x+6y = 8

28x = 17

We do not deal with fraction until we solve

3

step-by-step explanation: