Ashley school is selling tickets to the annual dance competition. on the first day of ticket sales the school sold 5 adult tickets and 9 student tickets for a total of $123. the school took in $183 on the second day by selling 13 adult tickets and 12 student tickets. find the price of an adult ticket and the price of a student ticket.

Price of an adult ticket is $3 and price of student ticket is $12 .

Step-by-step explanation:

Let us assume that the price of a adult ticket be x .

Let us assume that the price of a student ticket be y .

As given

ashley school is selling tickets to the annual dance competition.

On the first day of ticket sales the school sold 5 adult tickets and 9 student tickets for a total of $123.

The equation becomes

5x + 9y = 123

As given

The school took in $183 on the second day by selling 13 adult tickets and 12 student tickets.

The equation becomes

13x + 12y = 183

Two equations are

5x + 9y = 123

13x + 12y = 183

Multiply 5x + 9y = 123 by 13 .

65x + 117y = 1599

Mutiply 13x + 12y = 183 by 5

65x + 60y = 915

Subtracted 65x + 60y = 915  from 65x + 117y = 1599 .

65x - 65x + 117y - 60y = 1599 - 915

57y = 684

y = $12

Putting y = 12 in the equation

65x + 60 × 12 = 915

65x + 720 = 915

65x = 915 - 720

65x = 195

x =$ 3

Therefore the price of an adult ticket is $3 and price of student ticket is $12 .

after simplifying it i got: -36.25 as my answer. hope that !