The school that jack goes to is selling tickets to a choral performance. on the first day of ticket sales the school sold 9 senior citizen tickets and 8 student tickets for a total of $156. the school took in $163 on the second day by selling 7 senior citizen tickets and 9 student tickets. find the price of a senior citizen ticket and the price of a student ticket.

Price of a senior citizen ticket is $4 and price of a student ticket is $15 .

Step-by-step explanation:

Let us assume that the price a senior citizen ticket be x .

Let us assume that the price a student citizen ticket be y .

As given

The school that Jack goes to is selling tickets to a choral performance.

On the first day of ticket sales the school sold 9 senior citizen tickets and 8 student tickets for a total of $156.

Equtaions becomes

9x + 8y = 156

As given

The school took in $163 on the second day by selling 7 senior citizen tickets and 9 student tickets.

Equations becomes

7x + 9y = 163

Multipy 9x + 8y = 156 by 9 .

81x + 72y = 1404

Multiply 7x + 9y = 163  by 8 .

56x + 72y = 1304

Subtracted 56x + 72y = 1304 from 81x + 72y = 1404 .

81x - 56x + 72y - 72y = 1404 - 1304

25x = 100

x = $ 4

Putting value of x in the 56x + 72y = 1304 .

56 × 4 + 72y = 1304

224 + 72y = 1304

72y  = 1304 - 224

72y = 1080

y = $15

Therefore the price of a senior citizen ticket is $4 and price of a student ticket is $15 .

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph