Fast plz and you : d solve for x.

2x^2=72

−6 and 6
−8 and 8
−18 and 18
−36 and 36

x = -6, 6

Step-by-step explanation:

2x^2=72

Divide each side by 2

2/2x^2 =72/2

x^2 = 36

Take the square root of each side

sqrt(x^2) = ±sqrt(36)

x = ±6

if x = 1, then the answer is 3.5

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180