Taylor graphs the following in desmos and decides that f(x) = g(x) at x = 0, x = 1, & x = 3.

f(x) = 2x+1
g(x) = 2x^2+1

provide taylor some feedback that explains which part of the answer was incorrect and why.

  f(x) = g(x) at x=0 and x=1. The value of f(1)=g(1) is 3.

  At x=3, the function values are somewhat different.

Step-by-step explanation:

The points of intersection of the two functions are (0, 1) and (1, 3). One needs to pay attention to the question being asked and how these points relate to the answer.

Generally, when we're solving f(x)=g(x), we're only concerned with the values of x that make the equation true. When you graph both f(x) and g(x) and look for points of intersection, you also find the "y" values at which the equation is true. (If you graph f(x)-g(x) and look only for x-intercepts, there is no such issue.)

there is nothing below so i cannot

step-by-step explanation:

vertical asymptote .

horizontal asymptote .

step-by-step explanation:

given function is .

vertical asymptote is given by setting

denominator =0

when degree of numerator and denominator are same then divide first term of numerator by first term of denominator to get horizontal asymptote.