Which comparison is correct for the values of f(x) and g(x) when x=−3 ?

function a: f(x)=−x^2+4
function b:
x g(x)
−5 −2
−4 0
−3 1
−2 4

a. f(−3)
b. f(−3)=g(−3)

c. f(−3)> g(−3)

  A.  f(-3) < g(-3)

Step-by-step explanation:

Evaluating f(-3), you get ...

  f(-3) = -(-3)^2 +4 = -9 +4 = -5

Looking up g(-3) in the table, you get ...

  g(-3) = 1

Comparing these values, you find

  f(-3) vs. g(-3) . . . is . . .  -5 vs. 1

The true comparison is ...

  -5 < 1

So, f(-3) < g(-3).

range is infinite on both x and y axis positive and negative

step-by-step explanation:

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

hope this .