Apositive integer is twice another. the sum of the reciprocals of the two positive integers is 3/10 find the integers

x = 2y

1/x + 1/y = 3/10

Since we have a value for x, let's plug it into the second equation.

1/2y + 1/y = 3/10

Now, let's make the denominators equal.

Multiply the second term by 2.

1/2y + 2/2y = 3/10

Multiply the final term by 0.2y

1/2y + 2/2y = 0.6y/2y

Compare numerators after adding.

3 = 0.6y

Divide both sides by 0.6

Now that we have the value of the second integer, we can find the first.

x = 2y

x = 2(5)

Let's plug in these values in our equations to verify.

10 = 2(5) √ this is true

1/10 + 1/5 = 3/10 √ this is true

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

560

step-by-step explanation:

giggidy