Answer number three and shower work !

Approximately 21 inches of lead are needed to seal the edges of one sun catcher.  If the craftsperson has two 3-foot lengths of lead, 3 sun catchers can be sealed.

Step-by-step explanation:

The diagram of the sun catcher appears to make four right triangles, two of equal size on the top and two equal size on the bottom.  Since the base and height (legs) of each triangle are given, we can use the Pythagorean Theorem to find the missing side (hypotenuse) using the following formula:  

a² + b² = c², where 'a' and 'b' are the legs and 'c' is the hypotenuse

For the two top triangles a and b are both 2.75:

2.75² + 2.75² = c² or 15.125 = c²  take the square root:  √15.125 = √c²

c = 3.89 inches

For the bottom two triangles a = 2.75 and b = 5.5:

2.75² + 5.5² = c² or 37.8125 = c² take the square root: √37.8125 = √c²

c = 6.15 inches

For each sun catcher, you need to add all four sides of the triangles:

(2)(6.15) + (2)(3.89) ≈ 20.1 inches

With two 3 foot lengths of lead:

2 x 3 = 6 foot x 12 inches/foot = 72 inches

Total divided by the number needed per sun catcher:

72 ÷ 20.01 = 3.6, or 3 complete sun catchers

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841