Rick has 20 pints of green paint. he uses 2 5 of it to paint a landscape and 3 10 of it while painting a clover. he decides that, for his next painting, he will need 12 3 4 pints of green paint. how much more paint will he need to buy?

He needs to buy 6 and 3/4 more pints.

Step-by-step explanation:

In order to find this, we first need to find out how much he has used. To do this, add together the two fractions of the whole that he has used.

2/5 + 3/10

4/10 + 3/10 = 7/10

Since he has used 7/10 of it already, we can multiply that by the original amount to find how much is gone.

7/10 * 20 = 14

So with 14 pints having been used, we know there is 6 pints left. To find how many more he needs to buy, subtract 6 from the amount he needs for the next painting.

12 and 3/4 - 6 = 6 and 3/4

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841