Which point does not lie on the circle centered at a(3, 1) and passing through the origin (0, 0)? a. j(2, -2) b. k(6, 0) c. l(4, -4) d. m(2, 4)

The correct answer is C

Step-by-step explanation:

The given circle is centered at A(3, 1) and passes through the origin (0, 0).

The radius of this circle can be found using the distance formula;

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.

.

.

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The equation of this circle is given by

Where is the centre.

We substitute the center and radius to obtain;

Option A

When we substitute (2,-2) into this equation we get;

This is true

Option B

When we substitute K(6,0), we get,

This is also true

Option C

We substitute L(4,-4) to get;

This is false. Hence L(4,-4) does not lie on the circle.

Option D

We substitute M(2,4)

This is also true.

The correct answer is C

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.

351.23

step-by-step explanation: