Aperson on a runway sees a plane approaching. the angle of elevation from the runway to the plane is 11.1° . the altitude of the plane is 4000 fr. what is the horizontal distance from the plane to the person on the runway.

The horizontal distance from the plane to the person on the runway is 20408.16 ft.

Step-by-step explanation:

Consider the figure below,

Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner.  The angle of elevation from the runway to the plane is 11.1°

BC is the horizontal distance from the plane to the person on the runway.

We have to find distance BC,

Using trigonometric ratio,

Here, ,Perpendicular AB = 4000

Solving for BC, we get,

(approx)

(approx)  

Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft

which expression can be used to convert 80 us dollars (usd) to australian dollars (aud)?

1 usd = 1.0343 aud

1 aud = 0.9668 usd

step-by-step explanation:

sorry just need the points

there are infinitely many solutions.