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Mathematics, 05.10.2019 11:30 careykrysta

Solve for k j=k24
(a)k=±2j√j
(b)k=±4j√
(c)±4j
(d)k=±2j√

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Answers: 2

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Solve for k j=k24
(a)k=±2j√j
(b)k=±4j√
(c)±4j
(d)k=±2j√...
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