Points a, b, c, d, and o have coordinates (0, 3), (4, 4), (4, y), (4, 0), and (0, 0), respectively. the area of acdo is 5 times greater than the area of abdo. find y.

Solution:

Area of Quadrilateral ACDO= Area (ΔAOD)+Area(ΔACD)-----(1)

Area of Quadrilateral ABDO= Area (ΔAOD)+Area(ΔABD)------(2)

⇒ (1) = 5 ×(2)→→→→GIven

→Area (ΔAOD)+Area(ΔACD)=5 Area (ΔAOD)+5 Area(ΔABD),

→5 Area (ΔABD)+4 Area (ΔAOD)-Area (ΔACD)=0-----(3)

As, Area of a Triangle

Area (ΔACD)

Area (ΔABD)

Area  (ΔAOD)

Putting these values in equation (3)

→20+24-12+2 y=0

→  2 y= -32

Dividing both sides by , 2 we get

→y= -16

the two may have that, even a breakdown is probably offered

the answer is 2/54

step-by-step explanation: