Given: aklm is a trapezoid, ak=13
lm=14, kl=5, am=20
find: h

  h = 11.2

Step-by-step explanation:

Let point M' be a point on AM that is 5 units toward point A from M. Let point B lie on AM such that KB⊥AM. Let x = AB; then BM' = 15 -x. The Pythagorean theorem gives rise to two equations in x and h:

Subtracting the first from the second gives ...

  (225 -30x +x² + h²) - (x² + h²) = 196 -169

  225 -30x = 27

  x = 198/30 = 6.6

Then ...

  h = √(13² -x²) = √(169 -43.56) = √125.44

  h = 11.2

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation:

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation: