What are the zeros of the function f(x)=(x+16)(2x-3)(3x+4)

see explanation

Step-by-step explanation:

given f(x) in factored form, set f(x) = 0 and solve, that is

(x + 16)(2x - 3)(3x + 4) = 0

Equate each factor to zero and solve for x

x + 16 = 0 ⇒ x = - 16

2x - 3 = 0 ⇒ 2x = 3 ⇒ x =

3x + 4 = 0 ⇒ 3x = - 4 ⇒ x = -

The zeroes are

x = - 16, x = , x = -

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: