90
there are 4 jacks and 13 clubs in a standard, 52-card deck of playing cards. what is the probability that a card picked at random from a standard deck of playing cards is a club or a jack?
a.4/13
b.1/52
c.7/26
d.3/13
dont answer just to get points i needthe right answer if u cheat you get reported

a.4/13

Step-by-step explanation:

P ( jack or a club)

There are 4 jacks and 13 clubs, but 1 of the jacks is the jack of clubs

4+13 =17 but we cannot double count the jack of clubs

17-1 = 16

There are 16 cards that fit the jack or the club

P ( jack or a club) = P(jack) + P(clubs) - P(jack of clubs)

                             = 4/52  + 13/52  - 1/52

                             = 17/52 - 1/52

                             = 16/52

                              =4/13

1 of the jacks is a club,

So you would have a total of 16 cards to pick ( 3 jacks + 13 clubs)

There are 52 total cards.

The probability is the number of cards you want to pick ( 16) over the total number of cards in the deck (52)

Probability = 16/52 which can be reduced to a. 4/13

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

the answer would be 0.54