The area of a 5 in by 5 in square is the same as tye sum of areas of a 3 in by 3 in sauare and a 4 in by 4 in square. find two or more sauares that have the same total area as an 11 in by 11 in square

(2 in x 2 in) + (6 in x 6 in) + (9 in x 9 in) = (11 in x 11 in)

4 + 36 + 81 = 121

Step-by-step explanation:

Using perfect squares, we can find the sum of two or more squares that will equal an 11 in by 11 in square, or 121 in²:

2² + 6² + 9² = 4 + 36 + 81 = 121

So, 2 in by 2 in plus 6 in by 6 in plus 9 in by 9 in equals the total area of an 11 in by 11 in square.

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation